PPAD-Completeness of Contiguous Envy-Free Cake Cutting with Additive Valuations

Yasushi Kawase, Bodhayan Roy, Mohammad Azharuddin Sanpui
10/14/2026
cs.GTcs.AIcs.MA

No confident code implementation found for this paper.

Abstract

We prove that computing a complete contiguous $\varepsilon$-envy-free cake allocation is PPAD-complete for normalized rational piecewise-constant additive valuations. The hardness holds even when $\varepsilon$ is given in unary, and even when every density takes only two values, which are the same for all agents, and is piecewise constant with at most six breakpoints. As a consequence, computing an exact contiguous envy-free allocation is also PPAD-complete, and the hardness holds under the same restrictions on the densities. Our key ingredient is to assign prices to the pieces so that, in every approximately envy-free allocation, all prices are nearly equal, regardless of how the pieces are assigned to the agents. We further show that, for every fixed integer $c\ge1$, computing a contiguous EF$c$ allocation of indivisible goods on a path is PPAD-complete for additive valuations, and the hardness holds even for binary valuations in which each good is valued by exactly one agent and all agents value the same number of goods.

View on arXivView PDF

Code Implementations

No confident code match yet

We couldn't find an author-owned or strongly-evidenced community implementation for this paper. Any repos shown below are weak matches — verify before relying on them.

No code implementations found yet.

Know of an implementation? Let us know in the comments below!

Similar Papers

Cite this paper

@article{kawase2026ppadcompleteness,
  title  = {PPAD-Completeness of Contiguous Envy-Free Cake Cutting with Additive Valuations},
  author = {Yasushi Kawase and Bodhayan Roy and Mohammad Azharuddin Sanpui},
  year   = {2026},
  eprint = {2610.19690},
  archivePrefix = {arXiv},
  url    = {http://arxiv.org/abs/2610.19690v1}
}

Add a badge to your README

Shows whether official code is linked for this paper.

Code of Paper badge
[![Code of Paper](https://codeofpaper.com/badge/2610.19690.svg)](https://codeofpaper.com/paper/2610.19690)

Discussion